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1402227413339 is a prime number
BaseRepresentation
bin10100011001111011010…
…001000101000101011011
311222001101122021010011012
4110121323101011011123
5140433230204211324
62552101355524135
7203210334232334
oct24317321050533
94861348233135
101402227413339
114a0754900965
121a791715964b
13a22ca21602c
144bc2238128b
152671d99420e
hex1467b44515b

1402227413339 has 2 divisors, whose sum is σ = 1402227413340. Its totient is φ = 1402227413338.

The previous prime is 1402227413317. The next prime is 1402227413341. The reversal of 1402227413339 is 9333147222041.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1402227413339 is a prime.

Together with 1402227413341, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1402227413296 and 1402227413305.

It is not a weakly prime, because it can be changed into another prime (1402227413359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701113706669 + 701113706670.

It is an arithmetic number, because the mean of its divisors is an integer number (701113706670).

Almost surely, 21402227413339 is an apocalyptic number.

1402227413339 is a deficient number, since it is larger than the sum of its proper divisors (1).

1402227413339 is an equidigital number, since it uses as much as digits as its factorization.

1402227413339 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 217728, while the sum is 41.

The spelling of 1402227413339 in words is "one trillion, four hundred two billion, two hundred twenty-seven million, four hundred thirteen thousand, three hundred thirty-nine".