14022314134301 has 4 divisors (see below), whose sum is σ = 15297069964704. Its totient is φ = 12747558303900.

The previous prime is 14022314134291. The next prime is 14022314134303. The reversal of 14022314134301 is 10343141322041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14022314134301 - 2⁶ = 14022314134237 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14022314134303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 637377915185 + ... + 637377915206.

It is an arithmetic number, because the mean of its divisors is an integer number (3824267491176).

Almost surely, 2^{14022314134301} is an apocalyptic number.

14022314134301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14022314134301 is a deficient number, since it is larger than the sum of its proper divisors (1274755830403).

14022314134301 is a wasteful number, since it uses less digits than its factorization.

14022314134301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1274755830402.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 14022314134301 its reverse (10343141322041), we get a palindrome (24365455456342).

The spelling of 14022314134301 in words is "fourteen trillion, twenty-two billion, three hundred fourteen million, one hundred thirty-four thousand, three hundred one".