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140223434471 is a prime number
BaseRepresentation
bin1000001010010111110…
…1111100111011100111
3111101221102010112012222
42002211331330323213
54244134144400341
6144230122502555
713062603345521
oct2024575747347
9441842115188
10140223434471
115451752282a
1223214664a5b
13102b8c62a43
146b03190a11
1539aa65944b
hex20a5f7cee7

140223434471 has 2 divisors, whose sum is σ = 140223434472. Its totient is φ = 140223434470.

The previous prime is 140223434453. The next prime is 140223434551. The reversal of 140223434471 is 174434322041.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 140223434471 - 210 = 140223433447 is a prime.

It is a super-3 number, since 3×1402234344713 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140223434411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70111717235 + 70111717236.

It is an arithmetic number, because the mean of its divisors is an integer number (70111717236).

Almost surely, 2140223434471 is an apocalyptic number.

140223434471 is a deficient number, since it is larger than the sum of its proper divisors (1).

140223434471 is an equidigital number, since it uses as much as digits as its factorization.

140223434471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64512, while the sum is 35.

The spelling of 140223434471 in words is "one hundred forty billion, two hundred twenty-three million, four hundred thirty-four thousand, four hundred seventy-one".