140223443103301 has 4 divisors (see below), whose sum is σ = 140243483619532. Its totient is φ = 140203402587072.

The previous prime is 140223443103283. The next prime is 140223443103323. The reversal of 140223443103301 is 103301344322041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 94562691192225 + 45660751911076 = 9724335^2 + 6757274^2 .

It is a cyclic number.

It is not a de Polignac number, because 140223443103301 - 2³¹ = 140221295619653 is a prime.

It is a super-2 number, since 2×140223443103301² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140223443103101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10020247620 + ... + 10020261613.

It is an arithmetic number, because the mean of its divisors is an integer number (35060870904883).

Almost surely, 2^{140223443103301} is an apocalyptic number.

It is an amenable number.

140223443103301 is a deficient number, since it is larger than the sum of its proper divisors (20040516231).

140223443103301 is an equidigital number, since it uses as much as digits as its factorization.

140223443103301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20040516230.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 140223443103301 its reverse (103301344322041), we get a palindrome (243524787425342).

The spelling of 140223443103301 in words is "one hundred forty trillion, two hundred twenty-three billion, four hundred forty-three million, one hundred three thousand, three hundred one".