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140234213000000 = 2656720033459
BaseRepresentation
bin11111111000101011010010…
…011100111000001101000000
3200101112021000102022200222202
4133320223102130320031000
5121340044132012000000
61214130412540252332
741352405345655550
oct3770532234701500
9611467012280882
10140234213000000
1140756aa5381759
121388a3b62410a8
13603304cba2872
14268b52d175160
151132c31385dd5
hex7f8ad2738340

140234213000000 has 196 divisors, whose sum is σ = 397533883376160. Its totient is φ = 48080299200000.

The previous prime is 140234212999981. The next prime is 140234213000033. The reversal of 140234213000000 is 312432041.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 3016730 + ... + 17016729.

Almost surely, 2140234213000000 is an apocalyptic number.

140234213000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

140234213000000 is an abundant number, since it is smaller than the sum of its proper divisors (257299670376160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140234213000000 is an frugal number, since it uses more digits than its factorization.

140234213000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20033508 (or 20033473 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 140234213000000 its reverse (312432041), we get a palindrome (140234525432041).

The spelling of 140234213000000 in words is "one hundred forty trillion, two hundred thirty-four billion, two hundred thirteen million", and thus it is an aban number.