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1402343280889 is a prime number
BaseRepresentation
bin10100011010000010001…
…011000101000011111001
311222001200201021210112221
4110122002023011003321
5140433444334442024
62552121055204041
7203213242132525
oct24320213050371
94861621253487
101402343280889
114a080424a971
121a7949b16621
13a2318224005
144bc33902d85
1526728c303e4
hex146822c50f9

1402343280889 has 2 divisors, whose sum is σ = 1402343280890. Its totient is φ = 1402343280888.

The previous prime is 1402343280851. The next prime is 1402343280941. The reversal of 1402343280889 is 9880823432041.

It is an a-pointer prime, because the next prime (1402343280941) can be obtained adding 1402343280889 to its sum of digits (52).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 713700556864 + 688642724025 = 844808^2 + 829845^2 .

It is a cyclic number.

It is not a de Polignac number, because 1402343280889 - 211 = 1402343278841 is a prime.

It is not a weakly prime, because it can be changed into another prime (1402343287889) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701171640444 + 701171640445.

It is an arithmetic number, because the mean of its divisors is an integer number (701171640445).

Almost surely, 21402343280889 is an apocalyptic number.

It is an amenable number.

1402343280889 is a deficient number, since it is larger than the sum of its proper divisors (1).

1402343280889 is an equidigital number, since it uses as much as digits as its factorization.

1402343280889 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2654208, while the sum is 52.

The spelling of 1402343280889 in words is "one trillion, four hundred two billion, three hundred forty-three million, two hundred eighty thousand, eight hundred eighty-nine".