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140243240044421 is a prime number
BaseRepresentation
bin11111111000110011101100…
…100000010100011110000101
3200101120010022112022001222022
4133320303230200110132011
5121340221123422410141
61214134504405212525
741353145140405403
oct3770635440243605
9611503275261868
10140243240044421
114075a907964848
12138900b5401145
136033b5b131777
14268bb47dca473
1511330adb05b4b
hex7f8cec814785

140243240044421 has 2 divisors, whose sum is σ = 140243240044422. Its totient is φ = 140243240044420.

The previous prime is 140243240044409. The next prime is 140243240044423. The reversal of 140243240044421 is 124440042342041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118118314650625 + 22124925393796 = 10868225^2 + 4703714^2 .

It is a cyclic number.

It is not a de Polignac number, because 140243240044421 - 210 = 140243240043397 is a prime.

Together with 140243240044423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140243240044423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70121620022210 + 70121620022211.

It is an arithmetic number, because the mean of its divisors is an integer number (70121620022211).

Almost surely, 2140243240044421 is an apocalyptic number.

It is an amenable number.

140243240044421 is a deficient number, since it is larger than the sum of its proper divisors (1).

140243240044421 is an equidigital number, since it uses as much as digits as its factorization.

140243240044421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 98304, while the sum is 35.

Adding to 140243240044421 its reverse (124440042342041), we get a palindrome (264683282386462).

The spelling of 140243240044421 in words is "one hundred forty trillion, two hundred forty-three billion, two hundred forty million, forty-four thousand, four hundred twenty-one".