Base | Representation |
---|---|
bin | 1000001010011110101… |
… | …1000001001010010101 |
3 | 111102000101221002201201 |
4 | 2002213223001022111 |
5 | 4244214004303433 |
6 | 144233023352501 |
7 | 13063401355336 |
oct | 2024753011225 |
9 | 442011832651 |
10 | 140252025493 |
11 | 54531680678 |
12 | 23222152731 |
13 | 102c1b635c8 |
14 | 6b06cb428d |
15 | 39ace05a7d |
hex | 20a7ac1295 |
140252025493 has 2 divisors, whose sum is σ = 140252025494. Its totient is φ = 140252025492.
The previous prime is 140252025491. The next prime is 140252025509. The reversal of 140252025493 is 394520252041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100274822244 + 39977203249 = 316662^2 + 199943^2 .
It is a cyclic number.
It is not a de Polignac number, because 140252025493 - 21 = 140252025491 is a prime.
Together with 140252025491, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140252025491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70126012746 + 70126012747.
It is an arithmetic number, because the mean of its divisors is an integer number (70126012747).
Almost surely, 2140252025493 is an apocalyptic number.
It is an amenable number.
140252025493 is a deficient number, since it is larger than the sum of its proper divisors (1).
140252025493 is an equidigital number, since it uses as much as digits as its factorization.
140252025493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 140252025493 in words is "one hundred forty billion, two hundred fifty-two million, twenty-five thousand, four hundred ninety-three".
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