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14030011304341 is a prime number
BaseRepresentation
bin1100110000101001110111…
…0101110000100110010101
31211200020220121111011202221
43030022131311300212111
53314331430343214331
645501144225302341
72645430521260504
oct314123565604625
954606817434687
1014030011304341
11451a10468a84a
1216a713a4949b1
137aa0417764b6
143670b01ba83b
15194e45a0b711
hexcc29dd70995

14030011304341 has 2 divisors, whose sum is σ = 14030011304342. Its totient is φ = 14030011304340.

The previous prime is 14030011304333. The next prime is 14030011304363. The reversal of 14030011304341 is 14340311003041.

It is a happy number.

14030011304341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13994736830116 + 35274474225 = 3740954^2 + 187815^2 .

It is a cyclic number.

It is not a de Polignac number, because 14030011304341 - 23 = 14030011304333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14030011304321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7015005652170 + 7015005652171.

It is an arithmetic number, because the mean of its divisors is an integer number (7015005652171).

Almost surely, 214030011304341 is an apocalyptic number.

It is an amenable number.

14030011304341 is a deficient number, since it is larger than the sum of its proper divisors (1).

14030011304341 is an equidigital number, since it uses as much as digits as its factorization.

14030011304341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 14030011304341 its reverse (14340311003041), we get a palindrome (28370322307382).

The spelling of 14030011304341 in words is "fourteen trillion, thirty billion, eleven million, three hundred four thousand, three hundred forty-one".