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140313235153 = 7131541903683
BaseRepresentation
bin1000001010101101010…
…0100000111011010001
3111102011200002212121011
42002223110200323101
54244330142011103
6144243051330521
713065043551220
oct2025324407321
9442150085534
10140313235153
1154563188373
122323a750a41
1310301745040
146b11088cb7
1539b3496d6d
hex20ab520ed1

140313235153 has 8 divisors (see below), whose sum is σ = 172693212608. Its totient is φ = 111017065104.

The previous prime is 140313235129. The next prime is 140313235159. The reversal of 140313235153 is 351532313041.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140313235153 is a prime.

It is not an unprimeable number, because it can be changed into a prime (140313235159) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 770951751 + ... + 770951932.

It is an arithmetic number, because the mean of its divisors is an integer number (21586651576).

Almost surely, 2140313235153 is an apocalyptic number.

140313235153 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

140313235153 is a deficient number, since it is larger than the sum of its proper divisors (32379977455).

140313235153 is a wasteful number, since it uses less digits than its factorization.

140313235153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1541903703.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 140313235153 its reverse (351532313041), we get a palindrome (491845548194).

The spelling of 140313235153 in words is "one hundred forty billion, three hundred thirteen million, two hundred thirty-five thousand, one hundred fifty-three".

Divisors: 1 7 13 91 1541903683 10793325781 20044747879 140313235153