Base | Representation |
---|---|
bin | 1100110000101110110100… |
… | …0111000011111111101111 |
3 | 1211200101100021222220221102 |
4 | 3030023231013003333233 |
5 | 3314342141324142203 |
6 | 45501524214353315 |
7 | 2645505500452022 |
oct | 314135507037757 |
9 | 54611307886842 |
10 | 14031341240303 |
11 | 451a727374382 |
12 | 16a744b95b83b |
13 | 7aa1c416325a |
14 | 367198a911b9 |
15 | 194ec2661888 |
hex | cc2ed1c3fef |
14031341240303 has 4 divisors (see below), whose sum is σ = 14031350736648. Its totient is φ = 14031331743960.
The previous prime is 14031341240291. The next prime is 14031341240339. The reversal of 14031341240303 is 30304214313041.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 14031341240303 - 220 = 14031340191727 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14031341240603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002676 + ... + 5663337.
It is an arithmetic number, because the mean of its divisors is an integer number (3507837684162).
Almost surely, 214031341240303 is an apocalyptic number.
14031341240303 is a deficient number, since it is larger than the sum of its proper divisors (9496345).
14031341240303 is an equidigital number, since it uses as much as digits as its factorization.
14031341240303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9496344.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 14031341240303 its reverse (30304214313041), we get a palindrome (44335555553344).
The spelling of 14031341240303 in words is "fourteen trillion, thirty-one billion, three hundred forty-one million, two hundred forty thousand, three hundred three".
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