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140315010133 is a prime number
BaseRepresentation
bin1000001010101101101…
…1010010010001010101
3111102011210110001102011
42002223123102101111
54244331120311013
6144243153344221
713065064623124
oct2025333222125
9442153401364
10140315010133
115456418a9a1
122323b268071
1310301c16c1c
146b113cbabb
1539b36e7c3d
hex20ab6d2455

140315010133 has 2 divisors, whose sum is σ = 140315010134. Its totient is φ = 140315010132.

The previous prime is 140315010019. The next prime is 140315010167. The reversal of 140315010133 is 331010513041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132967434609 + 7347575524 = 364647^2 + 85718^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140315010133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140345010133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70157505066 + 70157505067.

It is an arithmetic number, because the mean of its divisors is an integer number (70157505067).

Almost surely, 2140315010133 is an apocalyptic number.

It is an amenable number.

140315010133 is a deficient number, since it is larger than the sum of its proper divisors (1).

140315010133 is an equidigital number, since it uses as much as digits as its factorization.

140315010133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 140315010133 its reverse (331010513041), we get a palindrome (471325523174).

The spelling of 140315010133 in words is "one hundred forty billion, three hundred fifteen million, ten thousand, one hundred thirty-three".