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140315525593 is a prime number
BaseRepresentation
bin1000001010101101110…
…1010000000111011001
3111102011211102020111021
42002223131100013121
54244331233304333
6144243212402441
713065102200665
oct2025335200731
9442154366437
10140315525593
11545645021a1
122323b476421
1310302067729
146b114c38a5
1539b379a82d
hex20ab7501d9

140315525593 has 2 divisors, whose sum is σ = 140315525594. Its totient is φ = 140315525592.

The previous prime is 140315525569. The next prime is 140315525617. The reversal of 140315525593 is 395525513041.

It is a balanced prime because it is at equal distance from previous prime (140315525569) and next prime (140315525617).

It can be written as a sum of positive squares in only one way, i.e., 133672134544 + 6643391049 = 365612^2 + 81507^2 .

It is a cyclic number.

It is not a de Polignac number, because 140315525593 - 237 = 2876572121 is a prime.

It is not a weakly prime, because it can be changed into another prime (140315520593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70157762796 + 70157762797.

It is an arithmetic number, because the mean of its divisors is an integer number (70157762797).

Almost surely, 2140315525593 is an apocalyptic number.

It is an amenable number.

140315525593 is a deficient number, since it is larger than the sum of its proper divisors (1).

140315525593 is an equidigital number, since it uses as much as digits as its factorization.

140315525593 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 405000, while the sum is 43.

The spelling of 140315525593 in words is "one hundred forty billion, three hundred fifteen million, five hundred twenty-five thousand, five hundred ninety-three".