14032412110231 has 4 divisors (see below), whose sum is σ = 14090637886864. Its totient is φ = 13974186333600.

The previous prime is 14032412110229. The next prime is 14032412110243. The reversal of 14032412110231 is 13201121423041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14032412110231 - 2¹ = 14032412110229 is a prime.

It is a super-2 number, since 2×14032412110231² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14032412110196 and 14032412110205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14032412110631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29112887955 + ... + 29112888436.

It is an arithmetic number, because the mean of its divisors is an integer number (3522659471716).

Almost surely, 2^{14032412110231} is an apocalyptic number.

14032412110231 is a deficient number, since it is larger than the sum of its proper divisors (58225776633).

14032412110231 is an equidigital number, since it uses as much as digits as its factorization.

14032412110231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58225776632.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14032412110231 its reverse (13201121423041), we get a palindrome (27233533533272).

The spelling of 14032412110231 in words is "fourteen trillion, thirty-two billion, four hundred twelve million, one hundred ten thousand, two hundred thirty-one".