Base | Representation |
---|---|
bin | 1100110000110101110010… |
… | …1011101100000000010101 |
3 | 1211200120011202020212122102 |
4 | 3030031130223230000111 |
5 | 3314410010024043331 |
6 | 45502434043211445 |
7 | 2645603050220633 |
oct | 314153453540025 |
9 | 54616152225572 |
10 | 14033213112341 |
11 | 45204a7a58565 |
12 | 16a7892816b85 |
13 | 7aa431bc8c47 |
14 | 3672d5516353 |
15 | 195081b654cb |
hex | cc35caec015 |
14033213112341 has 2 divisors, whose sum is σ = 14033213112342. Its totient is φ = 14033213112340.
The previous prime is 14033213112311. The next prime is 14033213112349. The reversal of 14033213112341 is 14321131233041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10102569830116 + 3930643282225 = 3178454^2 + 1982585^2 .
It is a cyclic number.
It is not a de Polignac number, because 14033213112341 - 26 = 14033213112277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14033213112349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7016606556170 + 7016606556171.
It is an arithmetic number, because the mean of its divisors is an integer number (7016606556171).
Almost surely, 214033213112341 is an apocalyptic number.
It is an amenable number.
14033213112341 is a deficient number, since it is larger than the sum of its proper divisors (1).
14033213112341 is an equidigital number, since it uses as much as digits as its factorization.
14033213112341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 14033213112341 its reverse (14321131233041), we get a palindrome (28354344345382).
The spelling of 14033213112341 in words is "fourteen trillion, thirty-three billion, two hundred thirteen million, one hundred twelve thousand, three hundred forty-one".
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