14033213112340 has 24 divisors (see below), whose sum is σ = 29469831592320. Its totient is φ = 5613269234208.

The previous prime is 14033213112311. The next prime is 14033213112341. The reversal of 14033213112340 is 4321131233041.

It is a junction number, because it is equal to n+sod(n) for n = 14033213112299 and 14033213112308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14033213112341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8290729 + ... + 9838831.

It is an arithmetic number, because the mean of its divisors is an integer number (1227909649680).

Almost surely, 2^{14033213112340} is an apocalyptic number.

14033213112340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14033213112340 is an abundant number, since it is smaller than the sum of its proper divisors (15436618479980).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14033213112340 is a wasteful number, since it uses less digits than its factorization.

14033213112340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2001351 (or 2001349 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 14033213112340 its reverse (4321131233041), we get a palindrome (18354344345381).

The spelling of 14033213112340 in words is "fourteen trillion, thirty-three billion, two hundred thirteen million, one hundred twelve thousand, three hundred forty".