Base | Representation |
---|---|
bin | 11111111010010001000000… |
… | …100010000101101111100110 |
3 | 200101220200221012222112100012 |
4 | 133322101000202011233212 |
5 | 121343341323103323332 |
6 | 1214252514502250222 |
7 | 41363323061342456 |
oct | 3772210042055746 |
9 | 611820835875305 |
10 | 140343434042342 |
11 | 40799352853403 |
12 | 138a75b8126972 |
13 | 6040437ba657b |
14 | 2692930b09d66 |
15 | 11359c4db13b2 |
hex | 7fa440885be6 |
140343434042342 has 4 divisors (see below), whose sum is σ = 210515151063516. Its totient is φ = 70171717021170.
The previous prime is 140343434042323. The next prime is 140343434042353. The reversal of 140343434042342 is 243240434343041.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 140343434042342.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35085858510584 + ... + 35085858510587.
It is an arithmetic number, because the mean of its divisors is an integer number (52628787765879).
Almost surely, 2140343434042342 is an apocalyptic number.
140343434042342 is a deficient number, since it is larger than the sum of its proper divisors (70171717021174).
140343434042342 is an equidigital number, since it uses as much as digits as its factorization.
140343434042342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70171717021173.
The product of its (nonzero) digits is 1327104, while the sum is 41.
Adding to 140343434042342 its reverse (243240434343041), we get a palindrome (383583868385383).
The spelling of 140343434042342 in words is "one hundred forty trillion, three hundred forty-three billion, four hundred thirty-four million, forty-two thousand, three hundred forty-two".
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