Base | Representation |
---|---|
bin | 1000001010110110000… |
… | …1001110111000011111 |
3 | 111102021020111222222010 |
4 | 2002231201032320133 |
5 | 4244414112423201 |
6 | 144250450122303 |
7 | 13066002236451 |
oct | 2025541167037 |
9 | 442236458863 |
10 | 140350123551 |
11 | 54581a93150 |
12 | 2324ab80393 |
13 | 1030928c4b1 |
14 | 6b15d2c2d1 |
15 | 39b6831bd6 |
hex | 20ad84ee1f |
140350123551 has 16 divisors (see below), whose sum is σ = 204240556800. Its totient is φ = 85021129920.
The previous prime is 140350123549. The next prime is 140350123553. The reversal of 140350123551 is 155321053041.
140350123551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (140350123549) and next prime (140350123553).
It is not a de Polignac number, because 140350123551 - 21 = 140350123549 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140350123553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 916651 + ... + 1058748.
It is an arithmetic number, because the mean of its divisors is an integer number (12765034800).
Almost surely, 2140350123551 is an apocalyptic number.
140350123551 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
140350123551 is a deficient number, since it is larger than the sum of its proper divisors (63890433249).
140350123551 is a wasteful number, since it uses less digits than its factorization.
140350123551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1977566.
The product of its (nonzero) digits is 9000, while the sum is 30.
Adding to 140350123551 its reverse (155321053041), we get a palindrome (295671176592).
It can be divided in two parts, 140350 and 123551, that added together give a triangular number (263901 = T726).
The spelling of 140350123551 in words is "one hundred forty billion, three hundred fifty million, one hundred twenty-three thousand, five hundred fifty-one".
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