Base | Representation |
---|---|
bin | 11111111010011000001010… |
… | …111110010011001000000010 |
3 | 200101221102210020122002102221 |
4 | 133322120022332103020002 |
5 | 121344003101100331424 |
6 | 1214300230015001254 |
7 | 41364014503666054 |
oct | 3772301276231002 |
9 | 611842706562387 |
10 | 140351125402114 |
11 | 407a163a385890 |
12 | 138a8ba3b0922a |
13 | 60410924b4c23 |
14 | 26930603d18d4 |
15 | 1135cc52429e4 |
hex | 7fa60af93202 |
140351125402114 has 8 divisors (see below), whose sum is σ = 229665477930768. Its totient is φ = 63795966091860.
The previous prime is 140351125402109. The next prime is 140351125402153. The reversal of 140351125402114 is 411204521153041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a self number, because there is not a number n which added to its sum of digits gives 140351125402114.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3189798304572 + ... + 3189798304615.
It is an arithmetic number, because the mean of its divisors is an integer number (28708184741346).
Almost surely, 2140351125402114 is an apocalyptic number.
140351125402114 is a deficient number, since it is larger than the sum of its proper divisors (89314352528654).
140351125402114 is a wasteful number, since it uses less digits than its factorization.
140351125402114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6379596609200.
The product of its (nonzero) digits is 19200, while the sum is 34.
Adding to 140351125402114 its reverse (411204521153041), we get a palindrome (551555646555155).
The spelling of 140351125402114 in words is "one hundred forty trillion, three hundred fifty-one billion, one hundred twenty-five million, four hundred two thousand, one hundred fourteen".
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