1403513130541 has 4 divisors (see below), whose sum is σ = 1423280921184. Its totient is φ = 1383745339900.

The previous prime is 1403513130533. The next prime is 1403513130559. The reversal of 1403513130541 is 1450313153041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1403513130541 - 2³ = 1403513130533 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1403513139541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9883895215 + ... + 9883895356.

It is an arithmetic number, because the mean of its divisors is an integer number (355820230296).

Almost surely, 2^{1403513130541} is an apocalyptic number.

It is an amenable number.

1403513130541 is a deficient number, since it is larger than the sum of its proper divisors (19767790643).

1403513130541 is an equidigital number, since it uses as much as digits as its factorization.

1403513130541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19767790642.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 1403513130541 its reverse (1450313153041), we get a palindrome (2853826283582).

The spelling of 1403513130541 in words is "one trillion, four hundred three billion, five hundred thirteen million, one hundred thirty thousand, five hundred forty-one".