140383471 has 2 divisors, whose sum is σ = 140383472. Its totient is φ = 140383470.

The previous prime is 140383459. The next prime is 140383483. The reversal of 140383471 is 174383041.

It is a balanced prime because it is at equal distance from previous prime (140383459) and next prime (140383483).

It is a cyclic number.

It is not a de Polignac number, because 140383471 - 2¹⁵ = 140350703 is a prime.

It is a super-3 number, since 3×140383471³ (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is equal to p_7932613 and since 140383471 and 7932613 have the same sum of digits, it is a Honaker prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140323471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70191735 + 70191736.

It is an arithmetic number, because the mean of its divisors is an integer number (70191736).

Almost surely, 2^140383471 is an apocalyptic number.

140383471 is a deficient number, since it is larger than the sum of its proper divisors (1).

140383471 is an equidigital number, since it uses as much as digits as its factorization.

140383471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 31.

The square root of 140383471 is about 11848.3530923078. The cubic root of 140383471 is about 519.7230662984.

The spelling of 140383471 in words is "one hundred forty million, three hundred eighty-three thousand, four hundred seventy-one".