Base | Representation |
---|---|
bin | 1100110001001111010000… |
… | …1100110110100001111000 |
3 | 1211201012211020022111221221 |
4 | 3030103310030312201320 |
5 | 3320013010313224422 |
6 | 45505524320241424 |
7 | 2646234350022043 |
oct | 314236414664170 |
9 | 54635736274857 |
10 | 14040050133112 |
11 | 4523396305453 |
12 | 16a9080470274 |
13 | 7aac8150a373 |
14 | 367783569c5a |
15 | 195331ed93c7 |
hex | cc4f4336878 |
14040050133112 has 64 divisors (see below), whose sum is σ = 26597917906560. Its totient is φ = 6947683891200.
The previous prime is 14040050133041. The next prime is 14040050133121. The reversal of 14040050133112 is 21133105004041.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 562872913 + ... + 562897855.
It is an arithmetic number, because the mean of its divisors is an integer number (415592467290).
Almost surely, 214040050133112 is an apocalyptic number.
It is an amenable number.
14040050133112 is a deficient number, since it is larger than the sum of its proper divisors (12557867773448).
14040050133112 is a wasteful number, since it uses less digits than its factorization.
14040050133112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26984 (or 26980 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 14040050133112 its reverse (21133105004041), we get a palindrome (35173155137153).
The spelling of 14040050133112 in words is "fourteen trillion, forty billion, fifty million, one hundred thirty-three thousand, one hundred twelve".
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