14040054551441 has 2 divisors, whose sum is σ = 14040054551442. Its totient is φ = 14040054551440.

The previous prime is 14040054551437. The next prime is 14040054551443. The reversal of 14040054551441 is 14415545004041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10553375971216 + 3486678580225 = 3248596^2 + 1867265^2 .

It is an emirp because it is prime and its reverse (14415545004041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14040054551441 - 2² = 14040054551437 is a prime.

Together with 14040054551443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14040054551395 and 14040054551404.

It is not a weakly prime, because it can be changed into another prime (14040054551443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020027275720 + 7020027275721.

It is an arithmetic number, because the mean of its divisors is an integer number (7020027275721).

Almost surely, 2^{14040054551441} is an apocalyptic number.

It is an amenable number.

14040054551441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14040054551441 is an equidigital number, since it uses as much as digits as its factorization.

14040054551441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 128000, while the sum is 38.

Adding to 14040054551441 its reverse (14415545004041), we get a palindrome (28455599555482).

The spelling of 14040054551441 in words is "fourteen trillion, forty billion, fifty-four million, five hundred fifty-one thousand, four hundred forty-one".