14040125501503 has 2 divisors, whose sum is σ = 14040125501504. Its totient is φ = 14040125501502.

The previous prime is 14040125501473. The next prime is 14040125501537. The reversal of 14040125501503 is 30510552104041.

It is a weak prime.

It is an emirp because it is prime and its reverse (30510552104041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14040125501503 - 2¹³ = 14040125493311 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14040125501603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020062750751 + 7020062750752.

It is an arithmetic number, because the mean of its divisors is an integer number (7020062750752).

Almost surely, 2^{14040125501503} is an apocalyptic number.

14040125501503 is a deficient number, since it is larger than the sum of its proper divisors (1).

14040125501503 is an equidigital number, since it uses as much as digits as its factorization.

14040125501503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 14040125501503 its reverse (30510552104041), we get a palindrome (44550677605544).

The spelling of 14040125501503 in words is "fourteen trillion, forty billion, one hundred twenty-five million, five hundred one thousand, five hundred three".