Base | Representation |
---|---|
bin | 1100110001001111110100… |
… | …1101001010110101100010 |
3 | 1211201020012202121002011221 |
4 | 3030103331031022311202 |
5 | 3320013313002224414 |
6 | 45505551314325254 |
7 | 2646241163122042 |
oct | 314237515126542 |
9 | 54636182532157 |
10 | 14040201211234 |
11 | 4523463613700 |
12 | 16a9102b8982a |
13 | 7aaca68c5bc3 |
14 | 367799655722 |
15 | 1953403cd224 |
hex | cc4fd34ad62 |
14040201211234 has 48 divisors (see below), whose sum is σ = 24933972903840. Its totient is φ = 5905414468800.
The previous prime is 14040201211217. The next prime is 14040201211241. The reversal of 14040201211234 is 43211210204041.
It is a junction number, because it is equal to n+sod(n) for n = 14040201211199 and 14040201211208.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 35308627 + ... + 35704054.
It is an arithmetic number, because the mean of its divisors is an integer number (519457768830).
Almost surely, 214040201211234 is an apocalyptic number.
14040201211234 is a deficient number, since it is larger than the sum of its proper divisors (10893771692606).
14040201211234 is a wasteful number, since it uses less digits than its factorization.
14040201211234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71012767 (or 71012756 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 14040201211234 its reverse (43211210204041), we get a palindrome (57251411415275).
The spelling of 14040201211234 in words is "fourteen trillion, forty billion, two hundred one million, two hundred eleven thousand, two hundred thirty-four".
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