Base | Representation |
---|---|
bin | 11111111011001001011101… |
… | …110001000100100110010111 |
3 | 200102010111101221020001101022 |
4 | 133323021131301010212113 |
5 | 121400340000314114343 |
6 | 1214340422035351355 |
7 | 41400600230043314 |
oct | 3773113561044627 |
9 | 612114357201338 |
10 | 140404054051223 |
11 | 408120302052a6 |
12 | 138b72b575255b |
13 | 6046078c16801 |
14 | 2695841a73d0b |
15 | 1137371c85568 |
hex | 7fb25dc44997 |
140404054051223 has 2 divisors, whose sum is σ = 140404054051224. Its totient is φ = 140404054051222.
The previous prime is 140404054051171. The next prime is 140404054051243. The reversal of 140404054051223 is 322150450404041.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140404054051223 - 228 = 140403785615767 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140404054051243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70202027025611 + 70202027025612.
It is an arithmetic number, because the mean of its divisors is an integer number (70202027025612).
Almost surely, 2140404054051223 is an apocalyptic number.
140404054051223 is a deficient number, since it is larger than the sum of its proper divisors (1).
140404054051223 is an equidigital number, since it uses as much as digits as its factorization.
140404054051223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 76800, while the sum is 35.
The spelling of 140404054051223 in words is "one hundred forty trillion, four hundred four billion, fifty-four million, fifty-one thousand, two hundred twenty-three".
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