Base | Representation |
---|---|
bin | 11111111011001010101110… |
… | …101111010101110111000100 |
3 | 200102010121220121111001021210 |
4 | 133323022232233111313010 |
5 | 121400400241103132012 |
6 | 1214341204525011420 |
7 | 41400646004105340 |
oct | 3773125657256704 |
9 | 612117817431253 |
10 | 140405412552132 |
11 | 4081266802a122 |
12 | 138b76146b3b70 |
13 | 60462344c52c0 |
14 | 2695930262620 |
15 | 113740117e23c |
hex | 7fb2aebd5dc4 |
140405412552132 has 96 divisors (see below), whose sum is σ = 404125738232832. Its totient is φ = 36946409625216.
The previous prime is 140405412552107. The next prime is 140405412552149. The reversal of 140405412552132 is 231255214504041.
It is a super-3 number, since 3×1404054125521323 (a number of 43 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 144636318 + ... + 145603829.
It is an arithmetic number, because the mean of its divisors is an integer number (4209643106592).
Almost surely, 2140405412552132 is an apocalyptic number.
140405412552132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
140405412552132 is an abundant number, since it is smaller than the sum of its proper divisors (263720325680700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140405412552132 is a wasteful number, since it uses less digits than its factorization.
140405412552132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 290240617 (or 290240615 counting only the distinct ones).
The product of its (nonzero) digits is 192000, while the sum is 39.
The spelling of 140405412552132 in words is "one hundred forty trillion, four hundred five billion, four hundred twelve million, five hundred fifty-two thousand, one hundred thirty-two".
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