Base | Representation |
---|---|
bin | 1100110001010010110101… |
… | …1110101010101000111010 |
3 | 1211201022022012112220121221 |
4 | 3030110231132222220322 |
5 | 3320021442320314224 |
6 | 45510203525222254 |
7 | 2646300226111255 |
oct | 314245536525072 |
9 | 54638265486557 |
10 | 14041011104314 |
11 | 45238397a1327 |
12 | 16a92aa26198a |
13 | 7ab0a5630a8c |
14 | 36783503809c |
15 | 19538b55b6e4 |
hex | cc52d7aaa3a |
14041011104314 has 4 divisors (see below), whose sum is σ = 21061516656474. Its totient is φ = 7020505552156.
The previous prime is 14041011104287. The next prime is 14041011104317. The reversal of 14041011104314 is 41340111014041.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13627282995225 + 413728109089 = 3691515^2 + 643217^2 .
It is not an unprimeable number, because it can be changed into a prime (14041011104317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3510252776077 + ... + 3510252776080.
Almost surely, 214041011104314 is an apocalyptic number.
14041011104314 is a deficient number, since it is larger than the sum of its proper divisors (7020505552160).
14041011104314 is an equidigital number, since it uses as much as digits as its factorization.
14041011104314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7020505552159.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 14041011104314 its reverse (41340111014041), we get a palindrome (55381122118355).
The spelling of 14041011104314 in words is "fourteen trillion, forty-one billion, eleven million, one hundred four thousand, three hundred fourteen".
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