Base | Representation |
---|---|
bin | 11111111011001111001100… |
… | …011011000110110001101101 |
3 | 200102011002021122022121120201 |
4 | 133323033030123012301231 |
5 | 121400440100103444440 |
6 | 1214343320303113501 |
7 | 41401205533544356 |
oct | 3773171433066155 |
9 | 612132248277521 |
10 | 140410205531245 |
11 | 408146a7599291 |
12 | 138b85318a2891 |
13 | 60468194ac010 |
14 | 2695c66a34d2d |
15 | 11375d1d4119a |
hex | 7fb3cc6c6c6d |
140410205531245 has 16 divisors (see below), whose sum is σ = 184528666465920. Its totient is φ = 101930120518464.
The previous prime is 140410205531213. The next prime is 140410205531261. The reversal of 140410205531245 is 542135502014041.
It is a cyclic number.
It is not a de Polignac number, because 140410205531245 - 25 = 140410205531213 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18306411489 + ... + 18306419158.
It is an arithmetic number, because the mean of its divisors is an integer number (11533041654120).
Almost surely, 2140410205531245 is an apocalyptic number.
It is an amenable number.
140410205531245 is a deficient number, since it is larger than the sum of its proper divisors (44118460934675).
140410205531245 is a wasteful number, since it uses less digits than its factorization.
140410205531245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36612830724.
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 140410205531245 its reverse (542135502014041), we get a palindrome (682545707545286).
The spelling of 140410205531245 in words is "one hundred forty trillion, four hundred ten billion, two hundred five million, five hundred thirty-one thousand, two hundred forty-five".
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