14041223433 has 24 divisors (see below), whose sum is σ = 20593154816. Its totient is φ = 9217216800.

The previous prime is 14041223419. The next prime is 14041223473. The reversal of 14041223433 is 33432214041.

14041223433 is a `hidden beast` number, since 1 + 4 + 0 + 4 + 1 + 223 + 433 = 666.

It is not a de Polignac number, because 14041223433 - 2⁵ = 14041223401 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14041223397 and 14041223406.

It is not an unprimeable number, because it can be changed into a prime (14041223473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2421768 + ... + 2427558.

Almost surely, 2^14041223433 is an apocalyptic number.

It is an amenable number.

14041223433 is a deficient number, since it is larger than the sum of its proper divisors (6551931383).

14041223433 is a wasteful number, since it uses less digits than its factorization.

14041223433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9885 (or 9882 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 14041223433 its reverse (33432214041), we get a palindrome (47473437474).

The spelling of 14041223433 in words is "fourteen billion, forty-one million, two hundred twenty-three thousand, four hundred thirty-three".