Base | Representation |
---|---|
bin | 1000001011000100111… |
… | …0011110001011000111 |
3 | 111102102120112121122121 |
4 | 2002301032132023013 |
5 | 4300031023024221 |
6 | 144300551110411 |
7 | 13100355656563 |
oct | 2026116361307 |
9 | 442376477577 |
10 | 140412314311 |
11 | 546040aaa75 |
12 | 23267972407 |
13 | 10319125669 |
14 | 6b202ba6a3 |
15 | 39bc018a41 |
hex | 20b139e2c7 |
140412314311 has 2 divisors, whose sum is σ = 140412314312. Its totient is φ = 140412314310.
The previous prime is 140412314309. The next prime is 140412314321. The reversal of 140412314311 is 113413214041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140412314311 - 21 = 140412314309 is a prime.
Together with 140412314309, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140412314321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70206157155 + 70206157156.
It is an arithmetic number, because the mean of its divisors is an integer number (70206157156).
Almost surely, 2140412314311 is an apocalyptic number.
140412314311 is a deficient number, since it is larger than the sum of its proper divisors (1).
140412314311 is an equidigital number, since it uses as much as digits as its factorization.
140412314311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 140412314311 its reverse (113413214041), we get a palindrome (253825528352).
The spelling of 140412314311 in words is "one hundred forty billion, four hundred twelve million, three hundred fourteen thousand, three hundred eleven".
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