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14042114103 = 319212965941
BaseRepresentation
bin11010001001111100…
…11010100000110111
31100020121201022021010
431010332122200313
5212224240122403
610241215123303
71004656000113
oct150476324067
940217638233
1014042114103
115a56453186
12287a813533
13142a265a74
14972d1a743
15572ba1603
hex344f9a837

14042114103 has 12 divisors (see below), whose sum is σ = 19760095608. Its totient is φ = 8868702960.

The previous prime is 14042114101. The next prime is 14042114129. The reversal of 14042114103 is 30141124041.

It is not a de Polignac number, because 14042114103 - 21 = 14042114101 is a prime.

It is a super-3 number, since 3×140421141033 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14042114103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14042114101) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6481888 + ... + 6484053.

It is an arithmetic number, because the mean of its divisors is an integer number (1646674634).

Almost surely, 214042114103 is an apocalyptic number.

14042114103 is a deficient number, since it is larger than the sum of its proper divisors (5717981505).

14042114103 is a wasteful number, since it uses less digits than its factorization.

14042114103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12965982 (or 12965963 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 14042114103 its reverse (30141124041), we get a palindrome (44183238144).

The spelling of 14042114103 in words is "fourteen billion, forty-two million, one hundred fourteen thousand, one hundred three".

Divisors: 1 3 19 57 361 1083 12965941 38897823 246352879 739058637 4680704701 14042114103