Base | Representation |
---|---|
bin | 11010001001111100… |
… | …11100100100101101 |
3 | 1100020121201201211122 |
4 | 31010332130210231 |
5 | 212224240410131 |
6 | 10241215230325 |
7 | 1004656033526 |
oct | 150476344455 |
9 | 40217651748 |
10 | 14042122541 |
11 | 5a56459557 |
12 | 287a8183a5 |
13 | 142a269865 |
14 | 972d1d84d |
15 | 572ba3d7b |
hex | 344f9c92d |
14042122541 has 8 divisors (see below), whose sum is σ = 14672495040. Its totient is φ = 13413403872.
The previous prime is 14042122537. The next prime is 14042122559. The reversal of 14042122541 is 14522124041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14042122541 - 22 = 14042122537 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 14042122541.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14042122511) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 396080 + ... + 430073.
It is an arithmetic number, because the mean of its divisors is an integer number (1834061880).
Almost surely, 214042122541 is an apocalyptic number.
It is an amenable number.
14042122541 is a deficient number, since it is larger than the sum of its proper divisors (630372499).
14042122541 is an equidigital number, since it uses as much as digits as its factorization.
14042122541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 826915.
The product of its (nonzero) digits is 2560, while the sum is 26.
Adding to 14042122541 its reverse (14522124041), we get a palindrome (28564246582).
The spelling of 14042122541 in words is "fourteen billion, forty-two million, one hundred twenty-two thousand, five hundred forty-one".
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