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140431321211143 is a prime number
BaseRepresentation
bin11111111011100010110111…
…000001000010000100000111
3200102020002210020012021221011
4133323202313001002010013
5121401311321212224033
61214401131445303051
741402554024061344
oct3773426701020407
9612202706167834
10140431321211143
1140822652872106
1213900645404a87
136048803067571
142696cab17b7cb
151137e1a9ddccd
hex7fb8b7042107

140431321211143 has 2 divisors, whose sum is σ = 140431321211144. Its totient is φ = 140431321211142.

The previous prime is 140431321211089. The next prime is 140431321211191. The reversal of 140431321211143 is 341112123134041.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140431321211143 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140431321211743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70215660605571 + 70215660605572.

It is an arithmetic number, because the mean of its divisors is an integer number (70215660605572).

Almost surely, 2140431321211143 is an apocalyptic number.

140431321211143 is a deficient number, since it is larger than the sum of its proper divisors (1).

140431321211143 is an equidigital number, since it uses as much as digits as its factorization.

140431321211143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 140431321211143 its reverse (341112123134041), we get a palindrome (481543444345184).

The spelling of 140431321211143 in words is "one hundred forty trillion, four hundred thirty-one billion, three hundred twenty-one million, two hundred eleven thousand, one hundred forty-three".