Base | Representation |
---|---|
bin | 11111111011100010110111… |
… | …000001000010000100000111 |
3 | 200102020002210020012021221011 |
4 | 133323202313001002010013 |
5 | 121401311321212224033 |
6 | 1214401131445303051 |
7 | 41402554024061344 |
oct | 3773426701020407 |
9 | 612202706167834 |
10 | 140431321211143 |
11 | 40822652872106 |
12 | 13900645404a87 |
13 | 6048803067571 |
14 | 2696cab17b7cb |
15 | 1137e1a9ddccd |
hex | 7fb8b7042107 |
140431321211143 has 2 divisors, whose sum is σ = 140431321211144. Its totient is φ = 140431321211142.
The previous prime is 140431321211089. The next prime is 140431321211191. The reversal of 140431321211143 is 341112123134041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140431321211143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140431321211743) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70215660605571 + 70215660605572.
It is an arithmetic number, because the mean of its divisors is an integer number (70215660605572).
Almost surely, 2140431321211143 is an apocalyptic number.
140431321211143 is a deficient number, since it is larger than the sum of its proper divisors (1).
140431321211143 is an equidigital number, since it uses as much as digits as its factorization.
140431321211143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 140431321211143 its reverse (341112123134041), we get a palindrome (481543444345184).
The spelling of 140431321211143 in words is "one hundred forty trillion, four hundred thirty-one billion, three hundred twenty-one million, two hundred eleven thousand, one hundred forty-three".
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