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14043310157 is a prime number
BaseRepresentation
bin11010001010000101…
…11110100001001101
31100020200222001221102
431011002332201031
5212230041411112
610241300512445
71005002111132
oct150502764115
940220861842
1014043310157
115a5709a858
12287b0ab725
13142a5942a6
1497314c589
15572d3abc2
hex3450be84d

14043310157 has 2 divisors, whose sum is σ = 14043310158. Its totient is φ = 14043310156.

The previous prime is 14043310147. The next prime is 14043310159. The reversal of 14043310157 is 75101334041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10772156521 + 3271153636 = 103789^2 + 57194^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14043310157 is a prime.

Together with 14043310159, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14043310159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7021655078 + 7021655079.

It is an arithmetic number, because the mean of its divisors is an integer number (7021655079).

Almost surely, 214043310157 is an apocalyptic number.

It is an amenable number.

14043310157 is a deficient number, since it is larger than the sum of its proper divisors (1).

14043310157 is an equidigital number, since it uses as much as digits as its factorization.

14043310157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 29.

Adding to 14043310157 its reverse (75101334041), we get a palindrome (89144644198).

The spelling of 14043310157 in words is "fourteen billion, forty-three million, three hundred ten thousand, one hundred fifty-seven".