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140433120150 = 235219316132593
BaseRepresentation
bin1000001011001001110…
…1110101101110010110
3111102111000200122220020
42002302131311232112
54300101334321100
6144303013050010
713101030553161
oct2026235655626
9442430618806
10140433120150
1154614920784
1223272926906
131032052b7cb
146b22d74ad8
1539bdc785a0
hex20b2775b96

140433120150 has 192 divisors, whose sum is σ = 379193825280. Its totient is φ = 34264166400.

The previous prime is 140433120133. The next prime is 140433120167. The reversal of 140433120150 is 51021334041.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (140433120133) and next prime (140433120167).

It is a super-2 number, since 2×1404331201502 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 140433120150.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 54157254 + ... + 54159846.

It is an arithmetic number, because the mean of its divisors is an integer number (1974967840).

Almost surely, 2140433120150 is an apocalyptic number.

140433120150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 140433120150, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (189596912640).

140433120150 is an abundant number, since it is smaller than the sum of its proper divisors (238760705130).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140433120150 is a wasteful number, since it uses less digits than its factorization.

140433120150 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3271 (or 3266 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 140433120150 its reverse (51021334041), we get a palindrome (191454454191).

The spelling of 140433120150 in words is "one hundred forty billion, four hundred thirty-three million, one hundred twenty thousand, one hundred fifty".