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14043323441 = 72006189063
BaseRepresentation
bin11010001010000110…
…00001110000110001
31100020200222202011102
431011003001300301
5212230042322231
610241301054145
71005002164640
oct150503016061
940220882142
1014043323441
115a570a9834
12287b0b7355
13142a59a354
14973153357
15572d3eacb
hex3450c1c31

14043323441 has 4 divisors (see below), whose sum is σ = 16049512512. Its totient is φ = 12037134372.

The previous prime is 14043323381. The next prime is 14043323443. The reversal of 14043323441 is 14432334041.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14043323441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14043323443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1003094525 + ... + 1003094538.

It is an arithmetic number, because the mean of its divisors is an integer number (4012378128).

Almost surely, 214043323441 is an apocalyptic number.

It is an amenable number.

14043323441 is a deficient number, since it is larger than the sum of its proper divisors (2006189071).

14043323441 is an equidigital number, since it uses as much as digits as its factorization.

14043323441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2006189070.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 14043323441 its reverse (14432334041), we get a palindrome (28475657482).

The spelling of 14043323441 in words is "fourteen billion, forty-three million, three hundred twenty-three thousand, four hundred forty-one".

Divisors: 1 7 2006189063 14043323441