Base | Representation |
---|---|
bin | 1000001011001010000… |
… | …1000001011001000011 |
3 | 111102111002021001020022 |
4 | 2002302201001121003 |
5 | 4300102043014441 |
6 | 144303043004055 |
7 | 13101040626254 |
oct | 2026241013103 |
9 | 442432231208 |
10 | 140433954371 |
11 | 54615340517 |
12 | 2327306962b |
13 | 10320761429 |
14 | 6b23110b2b |
15 | 39bdd9084b |
hex | 20b2841643 |
140433954371 has 2 divisors, whose sum is σ = 140433954372. Its totient is φ = 140433954370.
The previous prime is 140433954343. The next prime is 140433954373. The reversal of 140433954371 is 173459334041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140433954371 - 222 = 140429760067 is a prime.
It is a super-2 number, since 2×1404339543712 (a number of 23 digits) contains 22 as substring.
Together with 140433954373, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (140433954373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70216977185 + 70216977186.
It is an arithmetic number, because the mean of its divisors is an integer number (70216977186).
Almost surely, 2140433954371 is an apocalyptic number.
140433954371 is a deficient number, since it is larger than the sum of its proper divisors (1).
140433954371 is an equidigital number, since it uses as much as digits as its factorization.
140433954371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 544320, while the sum is 44.
The spelling of 140433954371 in words is "one hundred forty billion, four hundred thirty-three million, nine hundred fifty-four thousand, three hundred seventy-one".
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