14048739130511 has 2 divisors, whose sum is σ = 14048739130512. Its totient is φ = 14048739130510.

The previous prime is 14048739130507. The next prime is 14048739130513. The reversal of 14048739130511 is 11503193784041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14048739130511 - 2² = 14048739130507 is a prime.

It is a super-2 number, since 2×14048739130511² (a number of 27 digits) contains 22 as substring.

Together with 14048739130513, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14048739130513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7024369565255 + 7024369565256.

It is an arithmetic number, because the mean of its divisors is an integer number (7024369565256).

Almost surely, 2^{14048739130511} is an apocalyptic number.

14048739130511 is a deficient number, since it is larger than the sum of its proper divisors (1).

14048739130511 is an equidigital number, since it uses as much as digits as its factorization.

14048739130511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 362880, while the sum is 47.

The spelling of 14048739130511 in words is "fourteen trillion, forty-eight billion, seven hundred thirty-nine million, one hundred thirty thousand, five hundred eleven".