Base | Representation |
---|---|
bin | 11010001010110010… |
… | …11011111011111011 |
3 | 1100021010001012021222 |
4 | 31011121123323323 |
5 | 212233043312234 |
6 | 10242031022255 |
7 | 1005103132256 |
oct | 150531337373 |
9 | 40233035258 |
10 | 14049197819 |
11 | 5a5a451298 |
12 | 288106a98b |
13 | 142b876107 |
14 | 973c4209d |
15 | 57360042e |
hex | 34565befb |
14049197819 has 2 divisors, whose sum is σ = 14049197820. Its totient is φ = 14049197818.
The previous prime is 14049197761. The next prime is 14049197821. The reversal of 14049197819 is 91879194041.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14049197819 - 28 = 14049197563 is a prime.
It is a super-2 number, since 2×140491978192 (a number of 21 digits) contains 22 as substring.
Together with 14049197821, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14049197849) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7024598909 + 7024598910.
It is an arithmetic number, because the mean of its divisors is an integer number (7024598910).
Almost surely, 214049197819 is an apocalyptic number.
14049197819 is a deficient number, since it is larger than the sum of its proper divisors (1).
14049197819 is an equidigital number, since it uses as much as digits as its factorization.
14049197819 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 653184, while the sum is 53.
The spelling of 14049197819 in words is "fourteen billion, forty-nine million, one hundred ninety-seven thousand, eight hundred nineteen".
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