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14049752890013 is a prime number
BaseRepresentation
bin1100110001110011011010…
…0001111011101010011101
31211202010212102202122012122
43030130312201323222131
53320142343214440023
645514211204112325
72650026655056041
oct314346641735235
954663772678178
1014049752890013
114527515259305
1216aab299956a5
137abb69753839
14368024036021
151956edc302c8
hexcc73687ba9d

14049752890013 has 2 divisors, whose sum is σ = 14049752890014. Its totient is φ = 14049752890012.

The previous prime is 14049752889959. The next prime is 14049752890067. The reversal of 14049752890013 is 31009825794041.

It is a balanced prime because it is at equal distance from previous prime (14049752889959) and next prime (14049752890067).

It can be written as a sum of positive squares in only one way, i.e., 12730245794809 + 1319507095204 = 3567947^2 + 1148698^2 .

It is a cyclic number.

It is not a de Polignac number, because 14049752890013 - 210 = 14049752888989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14049752890813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7024876445006 + 7024876445007.

It is an arithmetic number, because the mean of its divisors is an integer number (7024876445007).

Almost surely, 214049752890013 is an apocalyptic number.

It is an amenable number.

14049752890013 is a deficient number, since it is larger than the sum of its proper divisors (1).

14049752890013 is an equidigital number, since it uses as much as digits as its factorization.

14049752890013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2177280, while the sum is 53.

The spelling of 14049752890013 in words is "fourteen trillion, forty-nine billion, seven hundred fifty-two million, eight hundred ninety thousand, thirteen".