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14050310153 = 111277300923
BaseRepresentation
bin11010001010111011…
…01011100000001001
31100021012010201010112
431011131223200021
5212233334411103
610242110524105
71005115444235
oct150535534011
940235121115
1014050310153
115a60040a80
122881506635
13142bb754b9
149740515c5
1557376ecd8
hex34576b809

14050310153 has 4 divisors (see below), whose sum is σ = 15327611088. Its totient is φ = 12773009220.

The previous prime is 14050310149. The next prime is 14050310167. The reversal of 14050310153 is 35101305041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14050310153 - 22 = 14050310149 is a prime.

It is a super-2 number, since 2×140503101532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (14050310753) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 638650451 + ... + 638650472.

It is an arithmetic number, because the mean of its divisors is an integer number (3831902772).

Almost surely, 214050310153 is an apocalyptic number.

It is an amenable number.

14050310153 is a deficient number, since it is larger than the sum of its proper divisors (1277300935).

14050310153 is a wasteful number, since it uses less digits than its factorization.

14050310153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1277300934.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 14050310153 its reverse (35101305041), we get a palindrome (49151615194).

The spelling of 14050310153 in words is "fourteen billion, fifty million, three hundred ten thousand, one hundred fifty-three".

Divisors: 1 11 1277300923 14050310153