Base | Representation |
---|---|
bin | 11010001011000001… |
… | …01111100001001011 |
3 | 1100021020122111110220 |
4 | 31011200233201023 |
5 | 212234041104120 |
6 | 10242140041123 |
7 | 1005125330061 |
oct | 150540574113 |
9 | 40236574426 |
10 | 14051113035 |
11 | 5a6053a213 |
12 | 28818331a3 |
13 | 142c096a8b |
14 | 9741c0031 |
15 | 57387cb40 |
hex | 34582f84b |
14051113035 has 32 divisors (see below), whose sum is σ = 24018274560. Its totient is φ = 6993537408.
The previous prime is 14051112983. The next prime is 14051113051. The reversal of 14051113035 is 53031115041.
It is not a de Polignac number, because 14051113035 - 214 = 14051096651 is a prime.
It is a super-2 number, since 2×140511130352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14051112996 and 14051113014.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 348832 + ... + 387021.
It is an arithmetic number, because the mean of its divisors is an integer number (750571080).
Almost surely, 214051113035 is an apocalyptic number.
14051113035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14051113035 is a deficient number, since it is larger than the sum of its proper divisors (9967161525).
14051113035 is a wasteful number, since it uses less digits than its factorization.
14051113035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 735947.
The product of its (nonzero) digits is 900, while the sum is 24.
Adding to 14051113035 its reverse (53031115041), we get a palindrome (67082228076).
The spelling of 14051113035 in words is "fourteen billion, fifty-one million, one hundred thirteen thousand, thirty-five".
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