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14051113035 = 351967735853
BaseRepresentation
bin11010001011000001…
…01111100001001011
31100021020122111110220
431011200233201023
5212234041104120
610242140041123
71005125330061
oct150540574113
940236574426
1014051113035
115a6053a213
1228818331a3
13142c096a8b
149741c0031
1557387cb40
hex34582f84b

14051113035 has 32 divisors (see below), whose sum is σ = 24018274560. Its totient is φ = 6993537408.

The previous prime is 14051112983. The next prime is 14051113051. The reversal of 14051113035 is 53031115041.

It is not a de Polignac number, because 14051113035 - 214 = 14051096651 is a prime.

It is a super-2 number, since 2×140511130352 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14051112996 and 14051113014.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 348832 + ... + 387021.

It is an arithmetic number, because the mean of its divisors is an integer number (750571080).

Almost surely, 214051113035 is an apocalyptic number.

14051113035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

14051113035 is a deficient number, since it is larger than the sum of its proper divisors (9967161525).

14051113035 is a wasteful number, since it uses less digits than its factorization.

14051113035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 735947.

The product of its (nonzero) digits is 900, while the sum is 24.

Adding to 14051113035 its reverse (53031115041), we get a palindrome (67082228076).

The spelling of 14051113035 in words is "fourteen billion, fifty-one million, one hundred thirteen thousand, thirty-five".

Divisors: 1 3 5 15 19 57 67 95 201 285 335 1005 1273 3819 6365 19095 735853 2207559 3679265 11037795 13981207 41943621 49302151 69906035 147906453 209718105 246510755 739532265 936740869 2810222607 4683704345 14051113035