Base | Representation |
---|---|
bin | 1100110010000000000010… |
… | …0100011000111110101111 |
3 | 1211202110121122222021220000 |
4 | 3030200000210120332233 |
5 | 3320221313442011030 |
6 | 45515531411555343 |
7 | 2650206654413166 |
oct | 314400044307657 |
9 | 54673548867800 |
10 | 14053142532015 |
11 | 45289a465a534 |
12 | 16ab714bbbb53 |
13 | 7ac289a90b72 |
14 | 3682662a83dd |
15 | 19584b5dd860 |
hex | cc800918faf |
14053142532015 has 20 divisors (see below), whose sum is σ = 25191559206264. Its totient is φ = 7495009350192.
The previous prime is 14053142532007. The next prime is 14053142532053. The reversal of 14053142532015 is 51023524135041.
14053142532015 is a `hidden beast` number, since 1 + 4 + 0 + 5 + 314 + 2 + 5 + 320 + 15 = 666.
It is not a de Polignac number, because 14053142532015 - 23 = 14053142532007 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 17349558277 + ... + 17349559086.
Almost surely, 214053142532015 is an apocalyptic number.
14053142532015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14053142532015 is a deficient number, since it is larger than the sum of its proper divisors (11138416674249).
14053142532015 is an equidigital number, since it uses as much as digits as its factorization.
14053142532015 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34699117380 (or 34699117371 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
Adding to 14053142532015 its reverse (51023524135041), we get a palindrome (65076666667056).
The spelling of 14053142532015 in words is "fourteen trillion, fifty-three billion, one hundred forty-two million, five hundred thirty-two thousand, fifteen".
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