Base | Representation |
---|---|
bin | 1100110010000101010000… |
… | …0000100101110100000111 |
3 | 1211202121020020010122202202 |
4 | 3030201110000211310013 |
5 | 3320232200330333133 |
6 | 45520322340425115 |
7 | 2650256443365563 |
oct | 314412400456407 |
9 | 54677206118682 |
10 | 14054542433543 |
11 | 4529552891247 |
12 | 16aba459a819b |
13 | 7ac450b06871 |
14 | 36835a1926a3 |
15 | 1958ce4642e8 |
hex | cc854025d07 |
14054542433543 has 2 divisors, whose sum is σ = 14054542433544. Its totient is φ = 14054542433542.
The previous prime is 14054542433501. The next prime is 14054542433557. The reversal of 14054542433543 is 34533424545041.
It is a strong prime.
It is an emirp because it is prime and its reverse (34533424545041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14054542433543 - 214 = 14054542417159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14054542433563) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7027271216771 + 7027271216772.
It is an arithmetic number, because the mean of its divisors is an integer number (7027271216772).
Almost surely, 214054542433543 is an apocalyptic number.
14054542433543 is a deficient number, since it is larger than the sum of its proper divisors (1).
14054542433543 is an equidigital number, since it uses as much as digits as its factorization.
14054542433543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912000, while the sum is 47.
Adding to 14054542433543 its reverse (34533424545041), we get a palindrome (48587966978584).
The spelling of 14054542433543 in words is "fourteen trillion, fifty-four billion, five hundred forty-two million, four hundred thirty-three thousand, five hundred forty-three".
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