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14054542433543 is a prime number
BaseRepresentation
bin1100110010000101010000…
…0000100101110100000111
31211202121020020010122202202
43030201110000211310013
53320232200330333133
645520322340425115
72650256443365563
oct314412400456407
954677206118682
1014054542433543
114529552891247
1216aba459a819b
137ac450b06871
1436835a1926a3
151958ce4642e8
hexcc854025d07

14054542433543 has 2 divisors, whose sum is σ = 14054542433544. Its totient is φ = 14054542433542.

The previous prime is 14054542433501. The next prime is 14054542433557. The reversal of 14054542433543 is 34533424545041.

It is a strong prime.

It is an emirp because it is prime and its reverse (34533424545041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14054542433543 - 214 = 14054542417159 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14054542433563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7027271216771 + 7027271216772.

It is an arithmetic number, because the mean of its divisors is an integer number (7027271216772).

Almost surely, 214054542433543 is an apocalyptic number.

14054542433543 is a deficient number, since it is larger than the sum of its proper divisors (1).

14054542433543 is an equidigital number, since it uses as much as digits as its factorization.

14054542433543 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912000, while the sum is 47.

Adding to 14054542433543 its reverse (34533424545041), we get a palindrome (48587966978584).

The spelling of 14054542433543 in words is "fourteen trillion, fifty-four billion, five hundred forty-two million, four hundred thirty-three thousand, five hundred forty-three".