14054542433552 has 10 divisors (see below), whose sum is σ = 27230675965038. Its totient is φ = 7027271216768.

The previous prime is 14054542433543. The next prime is 14054542433557. The reversal of 14054542433552 is 25533424545041.

It can be written as a sum of positive squares in only one way, i.e., 13761250867456 + 293291566096 = 3709616^2 + 541564^2 .

It is a super-3 number, since 3×14054542433552³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14054542433497 and 14054542433506.

It is not an unprimeable number, because it can be changed into a prime (14054542433557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 439204451033 + ... + 439204451064.

Almost surely, 2^{14054542433552} is an apocalyptic number.

It is an amenable number.

14054542433552 is a deficient number, since it is larger than the sum of its proper divisors (13176133531486).

14054542433552 is an equidigital number, since it uses as much as digits as its factorization.

14054542433552 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 878408902105 (or 878408902099 counting only the distinct ones).

The product of its (nonzero) digits is 5760000, while the sum is 47.

Adding to 14054542433552 its reverse (25533424545041), we get a palindrome (39587966978593).

The spelling of 14054542433552 in words is "fourteen trillion, fifty-four billion, five hundred forty-two million, four hundred thirty-three thousand, five hundred fifty-two".