Base | Representation |
---|---|
bin | 1100110010000111000010… |
… | …0111001101111100101111 |
3 | 1211202122110200010111020010 |
4 | 3030201300213031330233 |
5 | 3320234141203241310 |
6 | 45520442122224303 |
7 | 2650304361355653 |
oct | 314416047157457 |
9 | 54678420114203 |
10 | 14055022321455 |
11 | 4529779761125 |
12 | 16abb5a655093 |
13 | 7ac4c93694cb |
14 | 3683a3bd0a63 |
15 | 19590b658320 |
hex | cc8709cdf2f |
14055022321455 has 8 divisors (see below), whose sum is σ = 22488035714352. Its totient is φ = 7496011904768.
The previous prime is 14055022321433. The next prime is 14055022321463. The reversal of 14055022321455 is 55412322055041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14055022321455 - 28 = 14055022321199 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 468500744034 + ... + 468500744063.
It is an arithmetic number, because the mean of its divisors is an integer number (2811004464294).
Almost surely, 214055022321455 is an apocalyptic number.
14055022321455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14055022321455 is a deficient number, since it is larger than the sum of its proper divisors (8433013392897).
14055022321455 is an equidigital number, since it uses as much as digits as its factorization.
14055022321455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 937001488105.
The product of its (nonzero) digits is 240000, while the sum is 39.
Adding to 14055022321455 its reverse (55412322055041), we get a palindrome (69467344376496).
The spelling of 14055022321455 in words is "fourteen trillion, fifty-five billion, twenty-two million, three hundred twenty-one thousand, four hundred fifty-five".
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