Base | Representation |
---|---|
bin | 1100110010001000100001… |
… | …1001101000001110011111 |
3 | 1211202200111111002101212212 |
4 | 3030202020121220032133 |
5 | 3320241000340143010 |
6 | 45520545500151035 |
7 | 2650320305522666 |
oct | 314421031501637 |
9 | 54680444071785 |
10 | 14055421412255 |
11 | 4529963a65a33 |
12 | 16b005023847b |
13 | 7ac560c50002 |
14 | 368400bd9ddd |
15 | 1959316dc505 |
hex | cc88866839f |
14055421412255 has 4 divisors (see below), whose sum is σ = 16866505694712. Its totient is φ = 11244337129800.
The previous prime is 14055421412231. The next prime is 14055421412269. The reversal of 14055421412255 is 55221412455041.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 14055421412255 - 210 = 14055421411231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1405542141221 + ... + 1405542141230.
It is an arithmetic number, because the mean of its divisors is an integer number (4216626423678).
Almost surely, 214055421412255 is an apocalyptic number.
14055421412255 is a deficient number, since it is larger than the sum of its proper divisors (2811084282457).
14055421412255 is an equidigital number, since it uses as much as digits as its factorization.
14055421412255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2811084282456.
The product of its (nonzero) digits is 320000, while the sum is 41.
Adding to 14055421412255 its reverse (55221412455041), we get a palindrome (69276833867296).
The spelling of 14055421412255 in words is "fourteen trillion, fifty-five billion, four hundred twenty-one million, four hundred twelve thousand, two hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •