Base | Representation |
---|---|
bin | 11010001011100010… |
… | …01011100010101101 |
3 | 1100021112202102102211 |
4 | 31011301023202231 |
5 | 212241142002000 |
6 | 10242412250421 |
7 | 1005210055033 |
oct | 150561134255 |
9 | 40245672384 |
10 | 14055422125 |
11 | 5a62a12748 |
12 | 2883170a11 |
13 | 142cc45234 |
14 | 9749c2553 |
15 | 573e2e7ba |
hex | 345c4b8ad |
14055422125 has 16 divisors (see below), whose sum is σ = 17624333376. Its totient is φ = 11191026000.
The previous prime is 14055422119. The next prime is 14055422137. The reversal of 14055422125 is 52122455041.
14055422125 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14055422125 - 29 = 14055421613 is a prime.
It is a super-2 number, since 2×140554221252 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 240079 + ... + 292828.
It is an arithmetic number, because the mean of its divisors is an integer number (1101520836).
Almost surely, 214055422125 is an apocalyptic number.
It is an amenable number.
14055422125 is a deficient number, since it is larger than the sum of its proper divisors (3568911251).
14055422125 is an equidigital number, since it uses as much as digits as its factorization.
14055422125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 533133 (or 533123 counting only the distinct ones).
The product of its (nonzero) digits is 16000, while the sum is 31.
Adding to 14055422125 its reverse (52122455041), we get a palindrome (66177877166).
The spelling of 14055422125 in words is "fourteen billion, fifty-five million, four hundred twenty-two thousand, one hundred twenty-five".
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