14057183183471 has 2 divisors, whose sum is σ = 14057183183472. Its totient is φ = 14057183183470.

The previous prime is 14057183183401. The next prime is 14057183183473. The reversal of 14057183183471 is 17438138175041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14057183183471 - 2²² = 14057178989167 is a prime.

It is a super-3 number, since 3×14057183183471³ (a number of 40 digits) contains 333 as substring.

Together with 14057183183473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14057183183473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7028591591735 + 7028591591736.

It is an arithmetic number, because the mean of its divisors is an integer number (7028591591736).

Almost surely, 2^{14057183183471} is an apocalyptic number.

14057183183471 is a deficient number, since it is larger than the sum of its proper divisors (1).

14057183183471 is an equidigital number, since it uses as much as digits as its factorization.

14057183183471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2257920, while the sum is 53.

The spelling of 14057183183471 in words is "fourteen trillion, fifty-seven billion, one hundred eighty-three million, one hundred eighty-three thousand, four hundred seventy-one".